162x^4y^2+32y^2=

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Solution for 162x^4y^2+32y^2= equation:


Simplifying
162x4y2 + 32y2 = 0

Solving
162x4y2 + 32y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-32y2' to each side of the equation.
162x4y2 + 32y2 + -32y2 = 0 + -32y2

Combine like terms: 32y2 + -32y2 = 0
162x4y2 + 0 = 0 + -32y2
162x4y2 = 0 + -32y2
Remove the zero:
162x4y2 = -32y2

Divide each side by '162y2'.
x4 = -0.1975308642

Simplifying
x4 = -0.1975308642

Reorder the terms:
0.1975308642 + x4 = -0.1975308642 + 0.1975308642

Combine like terms: -0.1975308642 + 0.1975308642 = 0.0000000000
0.1975308642 + x4 = 0.0000000000

The solution to this equation could not be determined.

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